Advertisements
Advertisements
प्रश्न
Evaluate the following:
Γ(4)
योग
Advertisements
उत्तर
Γ(4) = Γ(3 + 1)
= 3!
= 6
shaalaa.com
Definite Integrals
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_0^{\pi/2} \sqrt{1 + \cos x}\ dx\]
\[\int\limits_0^2 \frac{1}{4 + x - x^2} dx\]
\[\int_0^1 \frac{1}{1 + 2x + 2 x^2 + 2 x^3 + x^4}dx\]
\[\int\limits_0^1 \tan^{- 1} x\ dx\]
\[\int\limits_0^1 \sqrt{\frac{1 - x}{1 + x}} dx\]
\[\int\limits_0^\pi x \cos^2 x\ dx\]
Evaluate :
\[\int\limits_2^3 3^x dx .\]
\[\int\limits_0^{\pi/2} \frac{\cos x}{1 + \sin^2 x} dx\]
If f(x) = `{{:(x^2"e"^(-2x)",", x ≥ 0),(0",", "otherwise"):}`, then evaluate `int_0^oo "f"(x) "d"x`
`int (x + 3)/(x + 4)^2 "e"^x "d"x` = ______.
