Advertisements
Advertisements
प्रश्न
Evaluate the following:
Γ(4)
योग
Advertisements
उत्तर
Γ(4) = Γ(3 + 1)
= 3!
= 6
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
\[\int\limits_1^e \frac{e^x}{x} \left( 1 + x \log x \right) dx\]
\[\int\limits_0^{\pi/2} \frac{1}{a^2 \sin^2 x + b^2 \cos^2 x} dx\]
\[\int\limits_0^{\pi/2} \cos^5 x\ dx\]
\[\int_0^\frac{\pi}{2} \sqrt{\cos x - \cos^3 x}\left( \sec^2 x - 1 \right) \cos^2 xdx\]
If f is an integrable function, show that
\[\int\limits_{- a}^a f\left( x^2 \right) dx = 2 \int\limits_0^a f\left( x^2 \right) dx\]
\[\int\limits_a^b e^x dx\]
\[\int\limits_0^{\pi/2} \cos x\ dx\]
The value of \[\int\limits_0^{2\pi} \sqrt{1 + \sin\frac{x}{2}}dx\] is
\[\int\limits_0^1 \frac{1 - x}{1 + x} dx\]
\[\int\limits_0^2 \left( x^2 + 2 \right) dx\]
