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1 ∫ 0 ( X E X + Cos P I X 4 ) D X

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Question

\[\int\limits_0^1 \left( x e^x + \cos\frac{\pi x}{4} \right) dx\]

 

Sum
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Solution

\[\text{Let }I = \int_0^1 \left( x e^x + \cos \frac{\pi x}{4} \right) d x . Then, \]

\[I = \int_0^1 x e^x dx + \int_0^1 \cos\frac{\pi x}{4} dx\]

\[\text{Integrating first term by parts}\]

\[I = \left\{ \left[ x e^x \right]_0^1 - \int_0^1 1 e^x dx \right\} + \left[ \frac{\sin \frac{\pi x}{4}}{\frac{\pi}{4}} \right]_0^1 \]

\[ \Rightarrow I = \left[ x e^x \right]_0^1 - \left[ e^x \right]_0^1 + \left[ \frac{\sin \frac{\pi x}{4}}{\frac{\pi}{4}} \right]_0^1 \]

\[ \Rightarrow I = e - e + 1 + \frac{4}{\pi} \sin \frac{\pi}{4}\]

\[ \Rightarrow I = 1 + \frac{4}{\pi\sqrt{2}}\]

\[ \Rightarrow I = 1 + \frac{2\sqrt{2}}{\pi}\]

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Notes

The answer given in the book has some error. The solution here is created according to the question given in the book.

  Is there an error in this question or solution?
Chapter 19: Definite Integrals - Exercise 20.1 [Page 17]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 19 Definite Integrals
Exercise 20.1 | Q 49 | Page 17
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