मराठी

1 ∫ 0 ( X E X + Cos P I X 4 ) D X

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प्रश्न

\[\int\limits_0^1 \left( x e^x + \cos\frac{\pi x}{4} \right) dx\]

 

बेरीज
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उत्तर

\[\text{Let }I = \int_0^1 \left( x e^x + \cos \frac{\pi x}{4} \right) d x . Then, \]

\[I = \int_0^1 x e^x dx + \int_0^1 \cos\frac{\pi x}{4} dx\]

\[\text{Integrating first term by parts}\]

\[I = \left\{ \left[ x e^x \right]_0^1 - \int_0^1 1 e^x dx \right\} + \left[ \frac{\sin \frac{\pi x}{4}}{\frac{\pi}{4}} \right]_0^1 \]

\[ \Rightarrow I = \left[ x e^x \right]_0^1 - \left[ e^x \right]_0^1 + \left[ \frac{\sin \frac{\pi x}{4}}{\frac{\pi}{4}} \right]_0^1 \]

\[ \Rightarrow I = e - e + 1 + \frac{4}{\pi} \sin \frac{\pi}{4}\]

\[ \Rightarrow I = 1 + \frac{4}{\pi\sqrt{2}}\]

\[ \Rightarrow I = 1 + \frac{2\sqrt{2}}{\pi}\]

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Notes

The answer given in the book has some error. The solution here is created according to the question given in the book.

  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Definite Integrals - Exercise 20.1 [पृष्ठ १७]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 19 Definite Integrals
Exercise 20.1 | Q 49 | पृष्ठ १७
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