English

Evaluate the Following Integral: ∫ π 2 0 Tan 7 X Tan 7 X + Cot 7 X D X

Advertisements
Advertisements

Question

Evaluate the following integral:

\[\int_0^\frac{\pi}{2} \frac{\tan^7 x}{\tan^7 x + \cot^7 x}dx\]
Sum
Advertisements

Solution

\[\text{Let I} = \int_0^\frac{\pi}{2} \frac{\tan^7 x}{\tan^7 x + \cot^7 x}dx.....................(1)\]

Then,

\[I = \int_0^\frac{\pi}{2} \frac{\tan^7 \left( \frac{\pi}{2} - x \right)}{\tan^7 \left( \frac{\pi}{2} - x \right) + \cot^7 \left( \frac{\pi}{2} - x \right)}dx ...................\left[ \int_0^a f\left( x \right)dx = \int_0^a f\left( a - x \right)dx \right]\]
\[ = \int_0^\frac{\pi}{2} \frac{\cot^7 x}{\cot^7 x + \tan^7 x}dx .................(2)\]

Adding (1) and (2), we get

\[2I = \int_0^\frac{\pi}{2} \frac{\tan^7 x + \cot^7 x}{\tan^7 x + \cot^7 x}dx\]
\[ \Rightarrow 2I = \int_0^\frac{\pi}{2} dx\]
\[ \Rightarrow 2I = \left.x\right|_0^\frac{\pi}{2} \]
\[ \Rightarrow 2I = \frac{\pi}{2} - 0 = \frac{\pi}{2}\]
\[ \Rightarrow I = \frac{\pi}{4}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 19: Definite Integrals - Exercise 20.5 [Page 95]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 19 Definite Integrals
Exercise 20.5 | Q 19 | Page 95

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Evaluate: `int1/(xlogxlog(logx))dx`


Evaluate : `int_0^4(|x|+|x-2|+|x-4|)dx`


Evaluate :

`∫_(-pi)^pi (cos ax−sin bx)^2 dx`


 

find `∫_2^4 x/(x^2 + 1)dx`

 

Evaluate the integral by using substitution.

`int_0^1 x/(x^2 +1)`dx


Evaluate the integral by using substitution.

`int_0^(pi/2) sqrt(sin phi) cos^5 phidphi`


Evaluate the integral by using substitution.

`int_0^2 xsqrt(x+2)`  (Put x + 2 = `t^2`)


Evaluate the integral by using substitution.

`int_0^(pi/2) (sin x)/(1+ cos^2 x) dx`


The value of the integral `int_(1/3)^4 ((x- x^3)^(1/3))/x^4` dx is ______.


If `f(x) = int_0^pi t sin  t  dt`, then f' (x) is ______.


Evaluate `int_0^(pi/4) (sinx + cosx)/(16 + 9sin2x) dx`


Evaluate: 

\[\int\sqrt{\frac{1 + \cos 2x}{2}}dx\]

Evaluate:

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]

Evaluate: 

\[\int\frac{1}{a^x b^x}dx\]

Evaluate:

\[\int\frac{\cos 2x + 2 \sin^2 x}{\sin^2 x}dx\]

Evaluate: 

\[\int\frac{2 \cos^2 x - \cos 2x}{\cos^2 x}dx\]

Evaluate the following integral:

\[\int\limits_0^2 \left| x^2 - 3x + 2 \right| dx\]

 


Evaluate the following integral:

\[\int\limits_0^{\pi/2} \left| \cos 2x \right| dx\]

Evaluate the following integral:

\[\int_2^8 \frac{\sqrt{10 - x}}{\sqrt{x} + \sqrt{10 - x}}dx\]

Evaluate the following integral:

\[\int_{- \pi}^\pi \frac{2x\left( 1 + \sin x \right)}{1 + \cos^2 x}dx\]

Evaluate : \[\int\limits_{- 2}^1 \left| x^3 - x \right|dx\] .


Evaluate: `int_1^5{|"x"-1|+|"x"-2|+|"x"-3|}d"x"`.


`int_0^1 x(1 - x)^5 "dx" =` ______.


`int_0^1 sin^-1 ((2x)/(1 + x^2))"d"x` = ______.


Evaluate the following:

`int "dt"/sqrt(3"t" - 2"t"^2)`


`int_0^1 x^2e^x dx` = ______.


The value of `int_0^1 (x^4(1 - x)^4)/(1 + x^2) dx` is


Evaluate: `int_0^(π/2) sin 2x tan^-1 (sin x) dx`.


Evaluate: `int x/(x^2 + 1)"d"x`


Evaluate:

`int (1 + cosx)/(sin^2x)dx`


If `int x^5 cos (x^6)dx = k sin (x^6) + C`, find the value of k.


In Method: Resubstitution, what should be done first?


If \[t=\tan^{-1}x\], what is \[dt\]?


What should not be added in a definite integral?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×