English

Evaluate the integral by using substitution. ∫12(1x-12x2)e2xdx

Advertisements
Advertisements

Question

Evaluate the integral by using substitution.

`int_1^2 (1/x- 1/(2x^2))e^(2x) dx`

Sum
Advertisements

Solution

Let `I = int_1^2 e^(2x) (1/x - 1/(2x^2))  dx`

Put 2x = t

⇒ 2dx = dt

When x = 1, t = 2

And when x = 2, t = 4

∴ `I = 1/2 int_2^4 e^t (2/t - (1 xx4)/(2t^2))  dt`

`= 1/2 int_2^4 e^t (2/t - 2/t^2) dt`

`= int_2^4 e^t* (1/t - 1/t^2) dt`

`= int_2^4 e^t *[1/t + d/dt (1/t)] dt`

`= [e^t * 1/t]_2^4 = 1/4 e^4 - e^2/2`

`= e^2/2 (e^2/2 - 1)`

or `(e^2 (e^2 - 2))/4`

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise 7.10 [Page 340]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.10 | Q 8 | Page 340

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Evaluate:  `int (1+logx)/(x(2+logx)(3+logx))dx`


Evaluate: `int1/(xlogxlog(logx))dx`


Evaluate : `int_0^4(|x|+|x-2|+|x-4|)dx`


Evaluate :

`∫_0^π(4x sin x)/(1+cos^2 x) dx`


Evaluate: `intsinsqrtx/sqrtxdx`

 


Evaluate of the following integral:

\[\int 3^{2 \log_3} {}^x dx\]

Evaluate of the following integral:

\[\int \log_x \text{x  dx}\] 

Evaluate : 

\[\int\frac{e^{6 \log_e x} - e^{5 \log_e x}}{e^{4 \log_e x} - e^{3 \log_e x}}dx\]

Evaluate:

\[\int\frac{\cos 2x + 2 \sin^2 x}{\sin^2 x}dx\]

Evaluate:

\[\int\frac{e\log \sqrt{x}}{x}dx\]

\[\int\frac{2x}{\left( 2x + 1 \right)^2} dx\]

Evaluate the following integral:

\[\int\limits_0^2 \left| x^2 - 3x + 2 \right| dx\]

 


Evaluate the following integral:

\[\int\limits_0^3 \left| 3x - 1 \right| dx\]

 


Evaluate the following integral:

\[\int\limits_0^{\pi/2} \left| \cos 2x \right| dx\]

Evaluate the following integral:

\[\int\limits_0^{2\pi} \left| \sin x \right| dx\]

 


Evaluate the following integral:

\[\int\limits_{- \pi/4}^{\pi/4} \left| \sin x \right| dx\]

Evaluate the following integral:

\[\int\limits_2^8 \left| x - 5 \right| dx\]

 


Evaluate the following integral:

\[\int\limits_0^4 \left| x - 1 \right| dx\]

Evaluate the following integral:

\[\int\limits_1^4 \left\{ \left| x - 1 \right| + \left| x - 2 \right| + \left| x - 4 \right| \right\} dx\]

 


Evaluate each of the following integral:

\[\int_{- \frac{\pi}{4}}^\frac{\pi}{4} \frac{\tan^2 x}{1 + e^x}dx\]

 


Evaluate each of the following integral:

\[\int_{- a}^a \frac{1}{1 + a^x}dx\]`, a > 0`

Evaluate each of the following integral:

\[\int_{- \frac{\pi}{4}}^\frac{\pi}{4} \frac{x^{11} - 3 x^9 + 5 x^7 - x^5 + 1}{\cos^2 x}dx\]

\[\int\limits_0^a \frac{\sqrt{x}}{\sqrt{x} + \sqrt{a - x}} dx\]

Evaluate the following integral:

\[\int_{- \frac{3\pi}{2}}^{- \frac{\pi}{2}} \left\{ \sin^2 \left( 3\pi + x \right) + \left( \pi + x \right)^3 \right\}dx\]

Evaluate the following integral:

\[\int_0^\pi \left( \frac{x}{1 + \sin^2 x} + \cos^7 x \right)dx\]

Evaluate the following integral:

\[\int_0^\frac{\pi}{2} \frac{a\sin x + b\sin x}{\sin x + \cos x}dx\]

 


Evaluate: `int_  e^x ((2+sin2x))/cos^2 x dx`


Evaluate: `int_1^5{|"x"-1|+|"x"-2|+|"x"-3|}d"x"`.


If `I_n = int_0^(pi/4) tan^n theta  "d"theta " then " I_8 + I_6` equals ______.


`int_0^(pi4) sec^4x  "d"x` = ______.


Find: `int (dx)/sqrt(3 - 2x - x^2)`


Evaluate: `int x/(x^2 + 1)"d"x`


Evaluate:

`int (1 + cosx)/(sin^2x)dx`


If `int x^5 cos (x^6)dx = k sin (x^6) + C`, find the value of k.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×