Advertisements
Advertisements
Question
Evaluate :
Advertisements
Solution
\[\int\left( \frac{e^{6 \log x} - e^{5 \ log x}}{e^{4 \ log x} - e^{3 \ log x}} \right)dx\]
`=∫( ( e^(log x^ 6) - e^(log x^5 ))/(e^(log x^4 )-e^(log x^3)))dx`
\[ = \int\left( \frac{x^6 - x^5}{x^4 - x^3} \right)dx\]
\[ = \int\frac{x^5}{x^3}dx\]
\[ = \int x^2 dx\]
\[ = \frac{x^3}{3} + C\]
APPEARS IN
RELATED QUESTIONS
Evaluate :`int_0^(pi/2)1/(1+cosx)dx`
Evaluate `int_(-1)^2|x^3-x|dx`
Evaluate :
`∫_(-pi)^pi (cos ax−sin bx)^2 dx`
find `∫_2^4 x/(x^2 + 1)dx`
If `int_0^a1/(4+x^2)dx=pi/8` , find the value of a.
Evaluate :
`int_e^(e^2) dx/(xlogx)`
Evaluate the integral by using substitution.
`int_0^2 xsqrt(x+2)` (Put x + 2 = `t^2`)
Evaluate the integral by using substitution.
`int_0^2 dx/(x + 4 - x^2)`
Evaluate the integral by using substitution.
`int_(-1)^1 dx/(x^2 + 2x + 5)`
Evaluate the integral by using substitution.
`int_1^2 (1/x- 1/(2x^2))e^(2x) dx`
If `f(x) = int_0^pi t sin t dt`, then f' (x) is ______.
Evaluate of the following integral:
Evaluate:
Evaluate:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Find : \[\int e^{2x} \sin \left( 3x + 1 \right) dx\] .
Evaluate: `int_-π^π (1 - "x"^2) sin "x" cos^2 "x" d"x"`.
Evaluate: `int_1^5{|"x"-1|+|"x"-2|+|"x"-3|}d"x"`.
`int_0^3 1/sqrt(3x - x^2)"d"x` = ______.
`int_0^(pi4) sec^4x "d"x` = ______.
Evaluate the following:
`int "dt"/sqrt(3"t" - 2"t"^2)`
The value of `int_0^1 (x^4(1 - x)^4)/(1 + x^2) dx` is
Evaluate:
`int (1 + cosx)/(sin^2x)dx`
