मराठी

Evaluate : ∫ E 6 Log E X − E 5 Log E X E 4 Log E X − E 3 Log E X D X

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प्रश्न

Evaluate : 

\[\int\frac{e^{6 \log_e x} - e^{5 \log_e x}}{e^{4 \log_e x} - e^{3 \log_e x}}dx\]
बेरीज
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उत्तर

\[\int\left( \frac{e^{6 \log x} - e^{5 \ log x}}{e^{4 \ log x} - e^{3 \ log x}} \right)dx\]

`=∫( ( e^(log x^ 6) - e^(log x^5 ))/(e^(log x^4 )-e^(log x^3)))dx` 
\[ = \int\left( \frac{x^6 - x^5}{x^4 - x^3} \right)dx\]
\[ = \int\frac{x^5}{x^3}dx\]
\[ = \int x^2 dx\]
\[ = \frac{x^3}{3} + C\]

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पाठ 18: Indefinite Integrals - Exercise 19.01 [पृष्ठ ४]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 18 Indefinite Integrals
Exercise 19.01 | Q 3 | पृष्ठ ४

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