Advertisements
Advertisements
प्रश्न
Evaluate of the following integral:
Advertisements
उत्तर
\[\int x^{- 5} dx\]
\[ = \frac{x^{- 5 + 1}}{- 5 + 1} + C\]
\[ = - \frac{1}{4} x^{- 4} + C\]
\[ = - \frac{1}{4 x^4} + C\]
APPEARS IN
संबंधित प्रश्न
Evaluate: `int (1+logx)/(x(2+logx)(3+logx))dx`
Evaluate :`int_0^(pi/2)1/(1+cosx)dx`
Evaluate: `int1/(xlogxlog(logx))dx`
Evaluate : `int1/(3+5cosx)dx`
Evaluate `∫_0^(3/2)|x cosπx|dx`
Evaluate `int_(-1)^2|x^3-x|dx`
find `∫_2^4 x/(x^2 + 1)dx`
Evaluate: `intsinsqrtx/sqrtxdx`
Evaluate the integral by using substitution.
`int_1^2 (1/x- 1/(2x^2))e^(2x) dx`
Evaluate of the following integral:
(i) \[\int x^4 dx\]
Evaluate:
Evaluate :
Evaluate:
Evaluate the following definite integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate
\[\int\limits_0^\pi \frac{x}{1 + \sin \alpha \sin x}dx\]
Evaluate the following integral:
Evaluate :
Find : \[\int e^{2x} \sin \left( 3x + 1 \right) dx\] .
Find: `int_ (3"x"+ 5)sqrt(5 + 4"x"-2"x"^2)d"x"`.
`int_0^1 x(1 - x)^5 "dx" =` ______.
`int_0^1 sin^-1 ((2x)/(1 + x^2))"d"x` = ______.
Evaluate the following:
`int ("e"^(6logx) - "e"^(5logx))/("e"^(4logx) - "e"^(3logx)) "d"x`
`int_0^1 x^2e^x dx` = ______.
Evaluate: `int_0^(π/2) sin 2x tan^-1 (sin x) dx`.
