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प्रश्न
find `∫_2^4 x/(x^2 + 1)dx`
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उत्तर
`∫_2^4 x/(x^2 + 1)dx`
`Put x^2+1=t`
`2xdx=dt`
Now, `1/2∫_5^17 1/tdt`
`⇒1/2log t_5^17`
`⇒1/2(log 17−log 5)`
`⇒1/2log (17/5)`
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