Advertisements
Advertisements
प्रश्न
If `int_0^a1/(4+x^2)dx=pi/8` , find the value of a.
Advertisements
उत्तर
given that `int_0^a1/(4+x^2)dx=pi/8`
We need to find the value of a.
`Let I=int_0^a1/(4+x^2)dx=pi/8`
`Thus,I=1/2(tan^(-1)(x/2))_0^a=pi/8`
`=>1/2 tan^(-1)(a/2)=pi/8`
`=>tan^(-1)(a/2)=pi/4`
`=>a/2=tan(pi/4)`
`=>a/2=1`
`a=2`
APPEARS IN
संबंधित प्रश्न
Evaluate :`int_0^(pi/2)1/(1+cosx)dx`
Evaluate : `int1/(3+5cosx)dx`
Evaluate :
`∫_(-pi)^pi (cos ax−sin bx)^2 dx`
find `∫_2^4 x/(x^2 + 1)dx`
Evaluate the integral by using substitution.
`int_0^(pi/2) sqrt(sin phi) cos^5 phidphi`
`int 1/(1 + cos x)` dx = _____
A) `tan(x/2) + c`
B) `2 tan (x/2) + c`
C) -`cot (x/2) + c`
D) -2 `cot (x/2)` + c
Evaluate of the following integral:
Evaluate of the following integral:
Evaluate:
Evaluate:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate :
Find: `int_ (3"x"+ 5)sqrt(5 + 4"x"-2"x"^2)d"x"`.
If `I_n = int_0^(pi/4) tan^n theta "d"theta " then " I_8 + I_6` equals ______.
Evaluate the following:
`int ("e"^(6logx) - "e"^(5logx))/("e"^(4logx) - "e"^(3logx)) "d"x`
Find: `int (dx)/sqrt(3 - 2x - x^2)`
Evaluate: `int x/(x^2 + 1)"d"x`
If `int x^5 cos (x^6)dx = k sin (x^6) + C`, find the value of k.
