मराठी

Evaluate the integral by using substitution. ∫01xx2+1dx

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प्रश्न

Evaluate the integral by using substitution.

`int_0^1 x/(x^2 +1)`dx

बेरीज
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उत्तर

Let  `int_0^1 x/(x^2 + 1)  dx`

Put x2 + 1 = t 

2x dx = dt

When x =1, t = 2; x = 0, t = 1

`therefore I = int_1^2  dt/t`

∴ `I = 1/2 int_1^2 dt/t = [1/2 log t]_1^2`

`= 1/2 [log 2 - log 1]`

`= 1/2 log 2`

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पाठ 7: Integrals - Exercise 7.10 [पृष्ठ ३४०]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 7 Integrals
Exercise 7.10 | Q 1 | पृष्ठ ३४०

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