Advertisements
Advertisements
प्रश्न
Evaluate the following integral:
Advertisements
उत्तर
\[\int_{- \frac{\pi}{4}}^\frac{\pi}{4} \left| \sin x \right| d x\]
\[\text{We know that}, \left| \sin x \right| = \begin{cases} - \sin x &,& - \frac{\pi}{4} \leq x \leq 0\\\sin x&,& 0 < x \leq \frac{\pi}{4}\end{cases}\]
\[ \therefore I = \int_{- \frac{\pi}{4}}^\frac{\pi}{4} \left| \sin x \right| d x\]
\[ \Rightarrow I = \int_{- \frac{\pi}{4}}^0 - \sin x dx + \int_0^\frac{\pi}{4} \sin x dx\]
\[ \Rightarrow I = \left[ \cos x \right]_\frac{- \pi}{4}^0 - \left[ \cos x \right]_0^\frac{- \pi}{4} \]
\[ \Rightarrow I = 1 - \frac{1}{\sqrt{2}} - \frac{1}{\sqrt{2}} + 1\]
\[ \Rightarrow I = 2 - \frac{2}{\sqrt{2}}\]
\[ \Rightarrow I = 2 - \sqrt{2}\]
APPEARS IN
संबंधित प्रश्न
Evaluate : `int_0^4(|x|+|x-2|+|x-4|)dx`
find `∫_2^4 x/(x^2 + 1)dx`
Evaluate: `intsinsqrtx/sqrtxdx`
Evaluate the integral by using substitution.
`int_(-1)^1 dx/(x^2 + 2x + 5)`
If `f(x) = int_0^pi t sin t dt`, then f' (x) is ______.
Evaluate of the following integral:
Evaluate of the following integral:
Evaluate of the following integral:
Evaluate:
Evaluate :
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate: \[\int\limits_0^{\pi/2} \frac{x \sin x \cos x}{\sin^4 x + \cos^4 x}dx\] .
Evaluate: `int_1^5{|"x"-1|+|"x"-2|+|"x"-3|}d"x"`.
Find: `int_ (3"x"+ 5)sqrt(5 + 4"x"-2"x"^2)d"x"`.
`int_(pi/5)^((3pi)/10) [(tan x)/(tan x + cot x)]`dx = ?
`int_0^1 x^2e^x dx` = ______.
The value of `int_0^1 (x^4(1 - x)^4)/(1 + x^2) dx` is
After finding the antiderivative in Method: Resubstitution, what is the next step?
Which limits are used to evaluate the resulting expression in Method: Resubstitution?
If the substitution is \[t=g(x)\], what differential relation is used in Method 2: Changing the Limits?
For the integral \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\], which substitution is suitable?
If \[t=\tan^{-1}x\], what is \[dt\]?
After using \[t=\tan^{-1}x\] in \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\], which integral results?
