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Evaluate the Following Integral: π / 4 ∫ − π / 4 | Sin X | D X

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प्रश्न

Evaluate the following integral:

\[\int\limits_{- \pi/4}^{\pi/4} \left| \sin x \right| dx\]
योग
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उत्तर

\[\int_{- \frac{\pi}{4}}^\frac{\pi}{4} \left| \sin x \right| d x\]
\[\text{We know that}, \left| \sin x \right| = \begin{cases} - \sin x &,& - \frac{\pi}{4} \leq x \leq 0\\\sin x&,& 0 < x \leq \frac{\pi}{4}\end{cases}\]
\[ \therefore I = \int_{- \frac{\pi}{4}}^\frac{\pi}{4} \left| \sin x \right| d x\]
\[ \Rightarrow I = \int_{- \frac{\pi}{4}}^0 - \sin x dx + \int_0^\frac{\pi}{4} \sin x dx\]
\[ \Rightarrow I = \left[ \cos x \right]_\frac{- \pi}{4}^0 - \left[ \cos x \right]_0^\frac{- \pi}{4} \]
\[ \Rightarrow I = 1 - \frac{1}{\sqrt{2}} - \frac{1}{\sqrt{2}} + 1\]
\[ \Rightarrow I = 2 - \frac{2}{\sqrt{2}}\]
\[ \Rightarrow I = 2 - \sqrt{2}\]

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अध्याय 19: Definite Integrals - Exercise 20.3 [पृष्ठ ५६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Exercise 20.3 | Q 13 | पृष्ठ ५६

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