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Evaluate the Following Integral: ∫ π 2 0 Tan 7 X Tan 7 X + Cot 7 X D X

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प्रश्न

Evaluate the following integral:

\[\int_0^\frac{\pi}{2} \frac{\tan^7 x}{\tan^7 x + \cot^7 x}dx\]
योग
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उत्तर

\[\text{Let I} = \int_0^\frac{\pi}{2} \frac{\tan^7 x}{\tan^7 x + \cot^7 x}dx.....................(1)\]

Then,

\[I = \int_0^\frac{\pi}{2} \frac{\tan^7 \left( \frac{\pi}{2} - x \right)}{\tan^7 \left( \frac{\pi}{2} - x \right) + \cot^7 \left( \frac{\pi}{2} - x \right)}dx ...................\left[ \int_0^a f\left( x \right)dx = \int_0^a f\left( a - x \right)dx \right]\]
\[ = \int_0^\frac{\pi}{2} \frac{\cot^7 x}{\cot^7 x + \tan^7 x}dx .................(2)\]

Adding (1) and (2), we get

\[2I = \int_0^\frac{\pi}{2} \frac{\tan^7 x + \cot^7 x}{\tan^7 x + \cot^7 x}dx\]
\[ \Rightarrow 2I = \int_0^\frac{\pi}{2} dx\]
\[ \Rightarrow 2I = \left.x\right|_0^\frac{\pi}{2} \]
\[ \Rightarrow 2I = \frac{\pi}{2} - 0 = \frac{\pi}{2}\]
\[ \Rightarrow I = \frac{\pi}{4}\]

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अध्याय 19: Definite Integrals - Exercise 20.5 [पृष्ठ ९५]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Exercise 20.5 | Q 19 | पृष्ठ ९५

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