हिंदी

A ∫ 0 √ X √ X + √ a − X D X

Advertisements
Advertisements

प्रश्न

\[\int\limits_0^a \frac{\sqrt{x}}{\sqrt{x} + \sqrt{a - x}} dx\]
योग
Advertisements

उत्तर

\[Let I = \int_0^a \frac{\sqrt{x}}{\sqrt{x} + \sqrt{a - x}} d x .............(1)\]

\[ \Rightarrow I = \int_0^a \frac{\sqrt{a - x}}{\sqrt{a - x} + \sqrt{x}}dx .....................\left[\text{Using, }\int_0^a f\left( x \right) dx = \int_0^a f\left( a - x \right) dx \right]\]
\[ \Rightarrow I = \int_0^a \frac{\sqrt{a - x}}{\sqrt{x} + \sqrt{a - x}}dx .......................(2)\]
\[\text{Adding (1) and } (2)\]
\[2I = \int_0^a \frac{\sqrt{x} + \sqrt{a - x}}{\sqrt{x} + \sqrt{a - x}} dx\]
\[ = \int_0^a dx = \left[ x \right]_0^a = a\]
\[Hence\ I = \frac{a}{2}\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Definite Integrals - Exercise 20.4 [पृष्ठ ६१]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 19 Definite Integrals
Exercise 20.4 | Q 12 | पृष्ठ ६१

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Evaluate:  `int (1+logx)/(x(2+logx)(3+logx))dx`


Evaluate :`int_0^(pi/2)1/(1+cosx)dx`

 


Evaluate: `int1/(xlogxlog(logx))dx`


 

Evaluate `int_(-1)^2|x^3-x|dx`

 

Evaluate :

`∫_0^π(4x sin x)/(1+cos^2 x) dx`


Evaluate the integral by using substitution.

`int_0^(pi/2) sqrt(sin phi) cos^5 phidphi`


Evaluate the integral by using substitution.

`int_0^2 dx/(x + 4 - x^2)`


Evaluate of the following integral: 

\[\int\frac{1}{x^5}dx\]

Evaluate of the following integral: 

\[\int 3^x dx\]

Evaluate:

\[\int\frac{\cos 2x + 2 \sin^2 x}{\sin^2 x}dx\]

\[\int\frac{2x}{\left( 2x + 1 \right)^2} dx\]

Evaluate the following integral:

\[\int\limits_0^{\pi/2} \left| \cos 2x \right| dx\]

Evaluate the following integral:

\[\int\limits_2^8 \left| x - 5 \right| dx\]

 


Evaluate the following integral:

\[\int\limits_0^4 \left( \left| x \right| + \left| x - 2 \right| + \left| x - 4 \right| \right) dx\]

Evaluate each of the following integral:

\[\int_0^{2\pi} \frac{e^\ sin x}{e^\ sin x + e^{- \ sin x}}dx\]

 


Evaluate each of the following integral:

\[\int_\frac{\pi}{6}^\frac{\pi}{3} \frac{\sqrt{\tan x}}{\sqrt{\tan x} + \sqrt{\cot x}}dx\]

Evaluate each of the following integral:

\[\int_{- \frac{\pi}{4}}^\frac{\pi}{4} \frac{\tan^2 x}{1 + e^x}dx\]

 


Evaluate the following integral:

\[\int_\frac{\pi}{6}^\frac{\pi}{3} \frac{1}{1 + \cot^\frac{3}{2} x}dx\]

 


Evaluate : 

\[\int\limits_0^{3/2} \left| x \sin \pi x \right|dx\]

Evaluate : \[\int\limits_{- 2}^1 \left| x^3 - x \right|dx\] .


Evaluate: \[\int\limits_0^{\pi/2} \frac{x \sin x \cos x}{\sin^4 x + \cos^4 x}dx\] .


Evaluate: `int_-π^π (1 - "x"^2) sin "x" cos^2 "x"  d"x"`.


Evaluate: `int_1^5{|"x"-1|+|"x"-2|+|"x"-3|}d"x"`.


`int_0^3 1/sqrt(3x - x^2)"d"x` = ______.


`int_0^(pi4) sec^4x  "d"x` = ______.


Each student in a class of 40, studies at least one of the subjects English, Mathematics and Economics. 16 study English, 22 Economics and 26 Mathematics, 5 study English and Economics, 14 Mathematics and Economics and 2 study all the three subjects. The number of students who study English and Mathematics but not Economics is


Evaluate: `int x/(x^2 + 1)"d"x`


If `int x^5 cos (x^6)dx = k sin (x^6) + C`, find the value of k.


After finding the antiderivative in Method: Resubstitution, what is the next step?


After changing the limits to the new variable, how is the definite integral completed?


If \[t=\tan^{-1}x\], what is \[dt\]?


After using \[t=\tan^{-1}x\] in \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\], which integral results?


What is the value of \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×