Question

Evaluate: `int1/(xlogxlog(logx))dx`

Answer 1

`Let I= int1/(x.logxlog(logx))dx`

Put log (log x) = t
Differentiating w.r.t. x, we get

`1/logx.1/xdx=dt`

`I=int1/tdt=log|t|+c`

`I=log|log(logx)|+c`