Advertisements
Advertisements
प्रश्न
Evaluate of the following integral:
Advertisements
उत्तर
\[\int\frac{dx}{x^{3/2}}\]
\[ = \int x^{- 3/2} dx\]
\[ = \left[ \frac{x^{- \frac{3}{2} + 1}}{\frac{- 3}{2} + 1} \right] + C\]
\[ = \left[ \frac{x^{- \frac{1}{2}}}{- \frac{1}{2}} \right] + C\]
\[ = - \frac{2}{\sqrt{x}} + C\]
APPEARS IN
संबंधित प्रश्न
Evaluate: `int1/(xlogxlog(logx))dx`
Evaluate : `int1/(3+5cosx)dx`
Evaluate `∫_0^(3/2)|x cosπx|dx`
Evaluate `int_(-1)^2|x^3-x|dx`
If `int_0^a1/(4+x^2)dx=pi/8` , find the value of a.
Evaluate: `intsinsqrtx/sqrtxdx`
Evaluate the integral by using substitution.
`int_(-1)^1 dx/(x^2 + 2x + 5)`
Evaluate the integral by using substitution.
`int_1^2 (1/x- 1/(2x^2))e^(2x) dx`
Evaluate of the following integral:
(i) \[\int x^4 dx\]
Evaluate of the following integral:
Evaluate of the following integral:
Evaluate:
Evaluate :
Evaluate the following integral:
Evaluate the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate each of the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate the following integral:
Evaluate: `int_-1^2 (|"x"|)/"x"d"x"`.
Find: `int (dx)/sqrt(3 - 2x - x^2)`
For the integral \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\], which substitution is suitable?
If \[t=\tan^{-1}x\], what is \[dt\]?
What is the value of \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\]?
