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Syllabus

Find: ∫dx3-2x-x2

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Question

Find: `int (dx)/sqrt(3 - 2x - x^2)`

Sum
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Solution

`int (dx)/sqrt(3 - 2x - x^2) = int (dx)/sqrt(-(x^2 + 2x - 3))`

= `int (dx)/sqrt(4 - (x + 1)^2`

= `sin^-1 ((x + 1)/2) + C`  .....`[int (dx)/sqrt(a^2 - x^2) = sin^-1 (x/a) + C]`

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Evaluation of Definite Integrals by Substitution
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Q 26
2022-2023 (March) Sample

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2022-2023 (March) Sample (with solutions)
Q 26 | 5 marks

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