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प्रश्न
Find: `int (dx)/sqrt(3 - 2x - x^2)`
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उत्तर
`int (dx)/sqrt(3 - 2x - x^2) = int (dx)/sqrt(-(x^2 + 2x - 3))`
= `int (dx)/sqrt(4 - (x + 1)^2`
= `sin^-1 ((x + 1)/2) + C` .....`[int (dx)/sqrt(a^2 - x^2) = sin^-1 (x/a) + C]`
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