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Evaluate: ∫ √ 1 − Cos 2 X 2 D X

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Question

Evaluate:

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]

Sum

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Solution

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]
`=∫ \sqrt {{2 sin_2 x }/{2}} dx` `[∴ 1 - cos 2x = 2 sin ^2 x]`
\[ = \int\text{sin x dx}\]
\[ = - \cos x + C\]

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Evaluation of Definite Integrals by Substitution

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Q 2.2 Q 2.1 Q 3

Chapter 18: Indefinite Integrals - Exercise 19.01 [Page 4]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12

Chapter 18 Indefinite Integrals
Exercise 19.01 | Q 2.2 | Page 4

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Evaluation of Definite Integrals by Substitution

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