English

Evaluate of the Following Integral: ∫ 1 3 √ X 2 D X

Advertisements
Advertisements

Question

Evaluate of the following integral:

\[\int\frac{1}{\sqrt[3]{x^2}}dx\]
Sum
Advertisements

Solution

\[\int\frac{dx}{\sqrt[3]{x^2}}\]
\[ = \int\frac{dx}{x^{2/3}}\]
\[ = \int x^{- 2/3} dx\]
\[ = \frac{x^{- \frac{2}{3} + 1}}{- \frac{2}{3} + 1} + C\]
\[ = 3 x^\frac{1}{3} + C\]
shaalaa.com
  Is there an error in this question or solution?
Chapter 18: Indefinite Integrals - Exercise 19.01 [Page 4]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 18 Indefinite Integrals
Exercise 19.01 | Q 1.6 | Page 4

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

 

Evaluate `∫_0^(3/2)|x cosπx|dx`

 

 

Evaluate `int_(-1)^2|x^3-x|dx`

 

 

find `∫_2^4 x/(x^2 + 1)dx`

 

Evaluate :

`int_e^(e^2) dx/(xlogx)`


Evaluate the integral by using substitution.

`int_0^1 x/(x^2 +1)`dx


Evaluate the integral by using substitution.

`int_0^(pi/2) (sin x)/(1+ cos^2 x) dx`


Evaluate the integral by using substitution.

`int_0^2 dx/(x + 4 - x^2)`


Evaluate `int_0^(pi/4) (sinx + cosx)/(16 + 9sin2x) dx`


Evaluate of the following integral: 

\[\int x^\frac{5}{4} dx\]

Evaluate:

\[\int\sqrt{\frac{1 - \cos 2x}{2}}dx\]

Evaluate : 

\[\int\frac{e^{6 \log_e x} - e^{5 \log_e x}}{e^{4 \log_e x} - e^{3 \log_e x}}dx\]

Evaluate the following integral:

\[\int\limits_{- 6}^6 \left| x + 2 \right| dx\]

 


Evaluate the following integral:

\[\int\limits_1^2 \left| x - 3 \right| dx\]

Evaluate the following integral:

\[\int\limits_0^4 \left| x - 1 \right| dx\]

Evaluate the following integral:

\[\int\limits_0^4 \left( \left| x \right| + \left| x - 2 \right| + \left| x - 4 \right| \right) dx\]

Evaluate each of the following integral:

\[\int_{- \frac{\pi}{4}}^\frac{\pi}{4} \frac{\tan^2 x}{1 + e^x}dx\]

 


Evaluate each of the following integral:

\[\int_{- \frac{\pi}{3}}^\frac{\pi}{3} \frac{1}{1 + e^\ tan\ x}dx\]

 


Evaluate the following integral:

\[\int_\frac{\pi}{6}^\frac{\pi}{3} \frac{1}{1 + \cot^\frac{3}{2} x}dx\]

 


Evaluate the following integral:

\[\int_0^\pi x\sin x \cos^2 xdx\]

Evaluate the following integral:

\[\int_{- \frac{3\pi}{2}}^{- \frac{\pi}{2}} \left\{ \sin^2 \left( 3\pi + x \right) + \left( \pi + x \right)^3 \right\}dx\]

Find : \[\int e^{2x} \sin \left( 3x + 1 \right) dx\] .


Evaluate: `int_-π^π (1 - "x"^2) sin "x" cos^2 "x"  d"x"`.


If `I_n = int_0^(pi/4) tan^n theta  "d"theta " then " I_8 + I_6` equals ______.


`int_0^1 x(1 - x)^5 "dx" =` ______.


`int_0^3 1/sqrt(3x - x^2)"d"x` = ______.


Evaluate the following:

`int "dt"/sqrt(3"t" - 2"t"^2)`


`int_0^1 x^2e^x dx` = ______.


The value of `int_0^1 (x^4(1 - x)^4)/(1 + x^2) dx` is


Evaluate: `int x/(x^2 + 1)"d"x`


Evaluate:

`int (1 + cosx)/(sin^2x)dx`


After finding the antiderivative in Method: Resubstitution, what is the next step?


After using \[t=\tan^{-1}x\] in \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\], which integral results?


What is the value of \[\int_{0}^{1}\frac{\tan^{-1}x}{1+x^2}\,dx\]?


What should not be added in a definite integral?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×