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Adjacent sides of a parallelogram are 11 cm and 17 cm. If the length of one of its diagonal is 26 cm, find the length of the other.
Concept: Apollonius Theorem
In the following figure, AE = EF = AF = BE = CF = a, AT ⊥ BC. Show that AB = AC = `sqrt3xxa`

Concept: Similarity in Right Angled Triangles
If the sides of a triangle are 6 cm, 8 cm and 10 cm, respectively, then determine whether the triangle is a right angle triangle or not.
Concept: Right-angled Triangles and Pythagoras Property
In triangle ABC, ∠C=90°. Let BC= a, CA= b, AB= c and let 'p' be the length of the perpendicular from 'C' on AB, prove that:
1. cp = ab
2. `1/p^2=1/a^2+1/b^2`
Concept: Right-angled Triangles and Pythagoras Property
In the given figure, ∠QPR = 90°, seg PM ⊥ seg QR and Q–M–R, PM = 10, QM = 8, find QR.

Concept: Theorem of Geometric Mean
For finding AB and BC with the help of information given in the figure, complete following activity.
AB = BC .......... 
∴ ∠BAC = 
∴ AB = BC =
× AC
=
× `sqrt8`
=
× `2sqrt2`
= 

Concept: Right-angled Triangles and Pythagoras Property
In the given figure, ∠DFE = 90°, FG ⊥ ED, If GD = 8, FG = 12, find (1) EG (2) FD and (3) EF

Concept: Right-angled Triangles and Pythagoras Property
Find the length diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.
Concept: Right-angled Triangles and Pythagoras Property
In the given figure, M is the midpoint of QR. ∠PRQ = 90°. Prove that, PQ2 = 4PM2 – 3PR2.

Concept: Right-angled Triangles and Pythagoras Property
Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.
Concept: Right-angled Triangles and Pythagoras Property
In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.
Concept: Right-angled Triangles and Pythagoras Property
In ∆ABC, point M is the midpoint of side BC. If, AB2 + AC2 = 290 cm2, AM = 8 cm, find BC.

Concept: Apollonius Theorem
In the given figure, point T is in the interior of rectangle PQRS, Prove that, TS2 + TQ2 = TP2 + TR2 (As shown in the figure, draw seg AB || side SR and A-T-B)

Concept: Right-angled Triangles and Pythagoras Property
Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:
Out of the dates given below which date constitutes a Pythagorean triplet?
Concept: Pythagorean Triplet
Some question and their alternative answer are given. Select the correct alternative.
Altitude on the hypotenuse of a right angled triangle divides it in two parts of lengths 4 cm and 9 cm. Find the length of the altitude.
Concept: Apollonius Theorem
Some question and their alternative answer are given. Select the correct alternative.
In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
Concept: Apollonius Theorem
Find the height of an equilateral triangle having side 2a.
Concept: Apollonius Theorem
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
Concept: Apollonius Theorem
Find the length of the hypotenuse of a right angled triangle if remaining sides are 9 cm and 12 cm.
Concept: Right-angled Triangles and Pythagoras Property
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.
Concept: Apollonius Theorem
