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Question
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
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Solution
According to Pythagoras theorem,
In ∆ABC
\[{AB}^2 + {BC}^2 = {AC}^2 \]
\[ \Rightarrow \left( 60 \right)^2 + \left( 11 \right)^2 = {AC}^2 \]
\[ \Rightarrow 3600 + 121 = {AC}^2 \]
\[ \Rightarrow {AC}^2 = 3721\]
\[ \Rightarrow AC = 61 cm\]
Hence, the length of a diagonal of the rectangle is 61 cm.
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