Advertisements
Advertisements
Question
Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.
Advertisements
Solution
According to Pythagoras theorem,
In ∆ABC
\[{AB}^2 + {BC}^2 = {AC}^2 \]
\[ \Rightarrow \left( 60 \right)^2 + \left( 11 \right)^2 = {AC}^2 \]
\[ \Rightarrow 3600 + 121 = {AC}^2 \]
\[ \Rightarrow {AC}^2 = 3721\]
\[ \Rightarrow AC = 61 cm\]
Hence, the length of a diagonal of the rectangle is 61 cm.
RELATED QUESTIONS
In ∆ABC, point M is the midpoint of side BC. If, AB2 + AC2 = 290 cm2, AM = 8 cm, find BC.
Find the perimeter of a square if its diagonal is `10sqrt2` cm:
Some question and their alternative answer are given. Select the correct alternative.
Altitude on the hypotenuse of a right angled triangle divides it in two parts of lengths 4 cm and 9 cm. Find the length of the altitude.
Some question and their alternative answer are given. Select the correct alternative.
In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.
Find the height of an equilateral triangle having side 2a.
A side of an isosceles right angled triangle is x. Find its hypotenuse.
In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.
In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.
Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.
Seg AM is a median of ∆ABC. If AB = 22, AC = 34, BC = 24, find AM
Choose the correct alternative:
Out of the following which is a Pythagorean triplet?
In ΔABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, then find the length of AP.
Choose the correct alternative:
Out of given triplets, which is not a Pythagoras triplet?
Choose the correct alternative:
Out of given triplets, which is not a Pythagoras triplet?
Choose the correct alternative:
Out of all numbers from given dates, which is a Pythagoras triplet?
In the given figure, triangle ABC is a right-angled at B. D is the mid-point of side BC. Prove that AC2 = 4AD2 – 3AB2.
