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Maharashtra State BoardSSC (English Medium) 10th Standard

In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST. - Geometry Mathematics 2

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Question

In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.

Sum
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Solution

In ∆RST,

∠S = 90, ∠T = 30,

∴ ∠R = 60

By the 30∘ − 60 − 90 theorem,

RS = `1/2` RT [Side opposite to 30°]

= `1/2 xx 12`

= 6 cm      ...(i)

Also,

ST = `sqrt3/2` [Side opposite to 60°]

= `sqrt3/2 xx 12`

= `6sqrt3` cm    ...(ii)

∴ RS = 6 cm and ST = `6sqrt3` cm

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Chapter 2: Pythagoras Theorem - Problem Set 2 [Page 44]

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Balbharati Mathematics 2 [English] Standard 10 Maharashtra State Board
Chapter 2 Pythagoras Theorem
Problem Set 2 | Q 3 | Page 44

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