हिंदी

In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.

Advertisements
Advertisements

प्रश्न

In ∆RST, ∠S = 90°, ∠T = 30°, RT = 12 cm, then find RS and ST.

योग
Advertisements

उत्तर

In ∆RST,

∠S = 90, ∠T = 30,

∴ ∠R = 60

By the 30∘ − 60 − 90 theorem,

RS = `1/2` RT [Side opposite to 30°]

= `1/2 xx 12`

= 6 cm      ...(i)

Also,

ST = `sqrt3/2` [Side opposite to 60°]

= `sqrt3/2 xx 12`

= `6sqrt3` cm    ...(ii)

∴ RS = 6 cm and ST = `6sqrt3` cm

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Pythagoras Theorem - Problem Set 2 [पृष्ठ ४४]

APPEARS IN

बालभारती Geometry Mathematics 2 [English] Standard 10 Maharashtra State Board
अध्याय 2 Pythagoras Theorem
Problem Set 2 | Q 3 | पृष्ठ ४४

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Adjacent sides of a parallelogram are 11 cm and 17 cm. If the length of one of its diagonal is 26 cm, find the length of the other.


In the given figure, seg PS is the median of ∆PQR and PT ⊥ QR. Prove that,

PR2 = PS2 + QR × ST + `("QR"/2)^2`


Out of the following, which is the Pythagorean triplet?


Some question and their alternative answer are given. Select the correct alternative.

Altitude on the hypotenuse of a right angled triangle divides it in two parts of lengths 4 cm and 9 cm. Find the length of the altitude.


Some question and their alternative answer are given. Select the correct alternative.

 In ∆ABC, AB = \[6\sqrt{3}\] cm, AC = 12 cm, BC = 6 cm. Find measure of ∠A.


Find the length a diagonal of a rectangle having sides 11 cm and 60 cm.


A side of an isosceles right angled triangle is x. Find its hypotenuse. 


In ∆ABC, seg AP is a median. If BC = 18, AB2 + AC2 = 260, Find AP.


Seg PM is a median of ∆PQR. If PQ = 40, PR = 42 and PM = 29, find QR.


If hypotenuse of a right angled triangle is 5 cm, find the radius of
the circle passing through all vertices of the triangle.


Choose the correct alternative: 

Out of the following which is a Pythagorean triplet? 


In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR. 


Out of given triplets, which is not a Pythagoras triplet?


Out of all numbers from given dates, which is a Pythagoras triplet?


Which of the following figure is formed by joining the mid-points of the adjacent sides of a square?


In the given figure, triangle ABC is a right-angled at B. D is the mid-point of side BC. Prove that AC2 = 4AD2 – 3AB2.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×