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In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2 = 290. Find the length of QR. - Geometry Mathematics 2

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प्रश्न

In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2  = 290. Find the length of QR. 

Seg PM is a median of ΔPQR, PM = 9 and PQ2 + PR2 = 290, then find QR.

योग
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उत्तर

Given: PM = 9,

PQ2 + PR2 = 290 

To find QR

∵ PM is the median of QR.

QM = MR   ...(i)

So, by apollonius theorem,

PQ2 + PR2 = 2 PM2 + 2 QM2 

290 = 2(9)2 + 2(QM)2 

290 = 2[81 + (QM)2

145 = 81 + QM2 

QM= 145 – 81

QM= 64

QM = 8

QM = MR = 8 units   ...[From (i)]

QR = QM + MR   ...[∵ QNR is a straight line]

QR = 8 + 8

QR = 16 units.

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