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In δPqr, Seg Pm is the Median. If Pm = 9, Pq2 + Pr2 = 290, Find Qr. - Geometry Mathematics 2

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प्रश्न

In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR. 

योग
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उत्तर

PM = 9 ; PQ2 + PR2 = 290 
To find QR

∵ PM is the median of QR.

So, by apollonius theorem,

PQ2 + PR2 = 2 PM2 + 2 QM2 

290 = 2(9)2 + 2(QM)2 

290 = 2 [81 + (QM)2

145 = 81 + QM2 

QM= 145 - 81

QM= 64

QM = 8

QM = 2 × QM = 2 × 8 = 16 units

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2013-2014 (October)

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