हिंदी

In δPqr, Seg Pm is the Median. If Pm = 9, Pq2 + Pr2 = 290, Find Qr.

Advertisements
Advertisements

प्रश्न

In ΔPQR, seg PM is the median. If PM = 9, PQ2 + PR2 = 290, Find QR. 

योग
Advertisements

उत्तर

PM = 9 ; PQ2 + PR2 = 290 
To find QR

∵ PM is the median of QR.

So, by apollonius theorem,

PQ2 + PR2 = 2 PM2 + 2 QM2 

290 = 2(9)2 + 2(QM)2 

290 = 2 [81 + (QM)2

145 = 81 + QM2 

QM= 145 - 81

QM= 64

QM = 8

QM = 2 × QM = 2 × 8 = 16 units

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2013-2014 (October)

APPEARS IN

वीडियो ट्यूटोरियलVIEW ALL [2]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×