Question

XOZ-plane divides the join of (2, 3, 1) and (6, 7, 1) in the ratio

Options

• 3 : 7

•  2 : 7

• –3 : 7

•  –2 : 7

Answer 1

 −3:7

Let A\[\equiv\](2, 3, 1) and B\[\equiv\]Let the line joining A and B be divided by the xz-plane at point P in the ratio\[\lambda: 1\] 

Then, we have,

P\[\equiv \left( \frac{6\lambda + 2}{\lambda + 1}, \frac{7\lambda + 3}{\lambda + 1}, \frac{\lambda + 1}{\lambda + 1} \right)\]

Since P lies on the xz-plane, the y-coordinate of P will be zero.

\[\therefore \frac{7\lambda + 3}{\lambda + 1} = 0\]
\[ \Rightarrow 7\lambda + 3 = 0\]
\[ \Rightarrow \lambda = \frac{- 3}{7}\]

Hence, the xz-plane divides AB in the ratio \[-\]3 : 7