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Let (3, 4, –1) and (–1, 2, 3) Be the End Points of a Diameter of a Sphere. Then, the Radius of the Sphere is Equal to

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Question

Let (3, 4, –1) and (–1, 2, 3) be the end points of a diameter of a sphere. Then, the radius of the sphere is equal to 

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  •  2

  • 3

  • 6

  • 7

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Solution

 3
Suppose d is the diameter of the sphere. Then 

\[d^2 = \left( - 1 - 3 \right)^2 + \left( 2 - 4 \right)^2 + \left( 3 + 1 \right)^2 \]
\[ \Rightarrow d^2 = \left( - 4 \right)^2 + \left( - 2 \right)^2 + \left( 4 \right)^2 \]
\[ \Rightarrow d^2 = 16 + 4 + 16\]
\[ \Rightarrow d^2 = 36\]
\[ \Rightarrow d = 6\] 

Hence, radius of the sphere is 3 units.

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Chapter 28: Introduction to three dimensional coordinate geometry - Exercise 28.5 [Page 23]

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R.D. Sharma Mathematics [English] Class 11
Chapter 28 Introduction to three dimensional coordinate geometry
Exercise 28.5 | Q 7 | Page 23

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