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Question
The unit vector normal to the plane x + 2y +3z – 6 = 0 is `1/sqrt(14)hati + 2/sqrt(14)hatj + 3/sqrt(14)hatk`.
Options
True
False
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Solution
This statement is True.
Explanation:
We have, `vecn = hati + 2hatj + 3hatk`
∴ `hatn = (hati + 2hatj + 3hatk)/sqrt(1^2 + 2^2 + 3^2)`
= `hati/sqrt(14) + (2hatj)/sqrt(14) + (3hatk)/sqrt(14)`
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