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Find the co-ordinates of the foot of perpendicular drawn from the point A(1, 8, 4) to the line joining the points B(0, –1, 3) and C(2, –3, –1). - Mathematics

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Question

Find the co-ordinates of the foot of perpendicular drawn from the point A(1, 8, 4) to the line joining the points B(0, –1, 3) and C(2, –3, –1).

Sum
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Solution

Let L be the foot of perpendicular drawn from the points A (1, 8, 4) to the line passing through B and C as shown in the Figure.

The equation of line BC by using formula `vecr = veca + lambda(vecb - veca)`, the equation of the line BC is

`vecr = (-hatj + 3hatk) + lambda(2hati - 2hatj - 4hatk)`

⇒ `xhati + yhati + xhatk = 2lambdahati - (2lambda + 1)hati + lambda(3 - 4lambda)hatk`

Comparing both sides, we get

`x = 2lambda, y = -(2lambda + 1), z = 3 - 4lambda`  ......(1)

Thus, the co-ordinate of L are `(2lambda, -(2lambda + 1), (3 - 4lambda)`

So that the direction ratios of the line AL are `(1 - 2lambda), 8 + (2lambda + 1), 4 - (3 - 4lambda)`

i.e. `1 - 2lambda, 2lambda + 9, 1 + 4lambda`

Since AL is perpendicular to BC, we have

(1 – 2λ) (2 – 0) + (2λ + 9) (–3 + 1) + (4λ + 1) (–1 –3) = 0

⇒ `lambda = (-5)/6`

The required point is obtained by substituting the value of λ, in (1), which is `((-5)/3, 2/3, 19/3)`.

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Chapter 12: Introduction to Three Dimensional Geometry - Solved Examples [Page 229]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Solved Examples | Q 11 | Page 229

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