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Planes Are Drawn Parallel to the Coordinate Planes Through the Points (3, 0, –1) and (–2, 5, 4). Find the Lengths of the Edges of the Parallelepiped So Formed.

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Question

Planes are drawn parallel to the coordinate planes through the points (3, 0, –1) and (–2, 5, 4). Find the lengths of the edges of the parallelepiped so formed.

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Solution

Let P\[\equiv\](3, 0, −1),  Q\[\equiv\](−2, 5, 4)

PE = Distance between the parallel planes ABCP and FQDE 

    =\[\left| 4 + 1 \right| = 5\]

 (These planes are perpendicular to the z-axis)
PA = Distance between the parallel planes ABQF and PCDE
  = \[\left| - 2 - 3 \right| = 5\]

(These planes are perpendicular to the x-axis)
Similarly, PC =\[\left| 5 - 0 \right| = 5\] 

Thus, the length of the edges of the parallelepiped are 5, 5 and 5

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Chapter 28: Introduction to three dimensional coordinate geometry - Exercise 15.1 [Page 6]

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R.D. Sharma Mathematics [English] Class 11
Chapter 28 Introduction to three dimensional coordinate geometry
Exercise 15.1 | Q 4 | Page 6

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