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The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is ______. - Mathematics

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Question

The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is ______.

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Solution

The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is `3hati + 4hatj - 7hatk + lambda|-2hati - 5hatj + 13hatk|`.

Explanation:

Given points are A(3, 4, –7), B(1, –1, 6) 

`vecA = 3hati + 4hatj - 7hatk`

`vecB = hati - hatj + 6hatk`

∴ Vector equation 

`vecr = (3hati + 4hatj - 7hatk) + lambda[hati - hatj + 6hatk - (3hati + 4hatj - 7hatk)]`

= `3hati + 4hatj - 7hatk + lambda[-2hati - 5hatj + 13hatk]`

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Chapter 12: Introduction to Three Dimensional Geometry - Exercise [Page 239]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Exercise | Q 40 | Page 239

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