English

The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is ______.

Advertisements
Advertisements

Question

The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is ______.

Fill in the Blanks
Advertisements

Solution

The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is `3hati + 4hatj - 7hatk + lambda|-2hati - 5hatj + 13hatk|`.

Explanation:

Given points are A(3, 4, –7), B(1, –1, 6) 

`vecA = 3hati + 4hatj - 7hatk`

`vecB = hati - hatj + 6hatk`

∴ Vector equation 

`vecr = (3hati + 4hatj - 7hatk) + lambda[hati - hatj + 6hatk - (3hati + 4hatj - 7hatk)]`

= `3hati + 4hatj - 7hatk + lambda[-2hati - 5hatj + 13hatk]`

shaalaa.com
  Is there an error in this question or solution?
Chapter 12: Introduction to Three Dimensional Geometry - Exercise [Page 239]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Exercise | Q 40 | Page 239

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

The x-axis and y-axis taken together determine a plane known as_______.


Three vertices of a parallelogram ABCD are A (3, –1, 2), B (1, 2, –4) and C (–1, 1, 2). Find the coordinates of the fourth vertex.


Name the octants in which the following points lie: 

(4, –3, 5)


Name the octants in which the following points lie: 

 (7, 4, –3)


Name the octants in which the following points lie:

 (2, –5, –7) 


Find the image  of: 

 (–4, 0, 0) in the xy-plane. 


Planes are drawn parallel to the coordinate planes through the points (3, 0, –1) and (–2, 5, 4). Find the lengths of the edges of the parallelepiped so formed.


Find the distances of the point P(–4, 3, 5) from the coordinate axes. 


The coordinates of a point are (3, –2, 5). Write down the coordinates of seven points such that the absolute values of their coordinates are the same as those of the coordinates of the given point.


Prove that the triangle formed by joining the three points whose coordinates are (1, 2, 3), (2, 3, 1) and (3, 1, 2) is an equilateral triangle.


Show that the points A(3, 3, 3), B(0, 6, 3), C(1, 7, 7) and D(4, 4, 7) are the vertices of a square.


If A(–2, 2, 3) and B(13, –3, 13) are two points.
Find the locus of a point P which moves in such a way the 3PA = 2PB.


Verify the following: 

 (0, 7, –10), (1, 6, –6) and (4, 9, –6) are vertices of an isosceles triangle.


Verify the following: 

 (0, 7, –10), (1, 6, –6) and (4, 9, –6) are vertices of an isosceles triangle. 


Find the locus of the point, the sum of whose distances from the points A(4, 0, 0) and B(–4, 0, 0) is equal to 10.


Find the equation of the set of the points P such that its distances from the points A(3, 4, –5) and B(–2, 1, 4) are equal.


Find the ratio in which the line segment joining the points (2, 4,5) and (3, −5, 4) is divided by the yz-plane.


XOZ-plane divides the join of (2, 3, 1) and (6, 7, 1) in the ratio


The length of the perpendicular drawn from the point P (3, 4, 5) on y-axis is 


Find the direction cosines of the line passing through the points P(2, 3, 5) and Q(–1, 2, 4).


The x-coordinate of a point on the line joining the points Q(2, 2, 1) and R(5, 1, –2) is 4. Find its z-coordinate.


If a line makes angles α, β, γ with the positive directions of the coordinate axes, then the value of sin2α + sin2β + sin2γ is ______.


Prove that the lines x = py + q, z = ry + s and x = p′y + q′, z = r′y + s′ are perpendicular if pp′ + rr′ + 1 = 0.


Find the equation of a plane which bisects perpendicularly the line joining the points A(2, 3, 4) and B(4, 5, 8) at right angles.


Find the angle between the lines whose direction cosines are given by the equations l + m + n = 0, l2 + m2 – n2 = 0


Find the foot of perpendicular from the point (2,3,–8) to the line `(4 - x)/2 = y/6 = (1 - z)/3`. Also, find the perpendicular distance from the given point to the line.


Show that the points `(hati - hatj + 3hatk)` and `3(hati + hatj + hatk)` are equidistant from the plane `vecr * (5hati + 2hatj - 7hatk) + 9` = 0 and lies on opposite side of it.


If the directions cosines of a line are k, k, k, then ______.


The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is ______.


The intercepts made by the plane 2x – 3y + 5z +4 = 0 on the co-ordinate axis are `-2, 4/3, - 4/5`.


The angle between the line `vecr = (5hati - hatj - 4hatk) + lambda(2hati - hatj + hatk)` and the plane `vec.(3hati - 4hatj - hatk)` + 5 = 0 is `sin^-1(5/(2sqrt(91)))`.


If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is `vecr.(5hati - 3hatj - 2hatk)` = 38.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×