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If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is r→.(5i^-3j^-2k^) = 38. - Mathematics

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Question

If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is `vecr.(5hati - 3hatj - 2hatk)` = 38.

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:


From the figure normal to the plane is `vecn = vec(OP) = 5hati - 3hatj - 2hatk`

Plane passing through the point P(5, – 3, – 2).

∴ Equation of the plane is `5(x - 5) - 3(y + 3) - 2(z + 2)` = 0

or `5x - 3y - 2z` = 38

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Chapter 12: Introduction to Three Dimensional Geometry - Exercise [Page 240]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Exercise | Q 49 | Page 240

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