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प्रश्न
If the foot of perpendicular drawn from the origin to a plane is (5, – 3, – 2), then the equation of plane is `vecr.(5hati - 3hatj - 2hatk)` = 38.
विकल्प
True
False
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उत्तर
This statement is True.
Explanation:
From the figure normal to the plane is `vecn = vec(OP) = 5hati - 3hatj - 2hatk`
Plane passing through the point P(5, – 3, – 2).
∴ Equation of the plane is `5(x - 5) - 3(y + 3) - 2(z + 2)` = 0
or `5x - 3y - 2z` = 38
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