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The vector equation of the line x-53=y+47=z-62 is r→=(5i^-4j^+6k^)+λ(3i^+7j^-2k^).

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Question

The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is `vecr = (5hati - 4hatj + 6hatk) + lambda(3hati + 7hatj - 2hatk)`.

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:

We have given line as `(x - 5)/3 = (y + 4)/7 = (z - 6)/2`

By comparing with equation

`(x - x_1)/a = (y - y_1)/b = (z - z_1)/c`

We get given line passes through the point (x1 , x2 , x3 )

i.e., (5, - 4, 6) and direction ratios are (a, b, c)

i.e., (3, 7, –2).

Now, we can write vector equation of the line as `vecr = (5hati - 4hatj + 6hatk) + lambda(3hati + 7hatj - 2hatk)`

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Chapter 12: Introduction to Three Dimensional Geometry - Exercise [Page 239]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Exercise | Q 47 | Page 239

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