मराठी

The vector equation of the line x-53=y+47=z-62 is r→=(5i^-4j^+6k^)+λ(3i^+7j^-2k^).

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प्रश्न

The vector equation of the line `(x - 5)/3 = (y + 4)/7 = (z - 6)/2` is `vecr = (5hati - 4hatj + 6hatk) + lambda(3hati + 7hatj - 2hatk)`.

पर्याय

  • True

  • False

MCQ
चूक किंवा बरोबर
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उत्तर

This statement is True.

Explanation:

We have given line as `(x - 5)/3 = (y + 4)/7 = (z - 6)/2`

By comparing with equation

`(x - x_1)/a = (y - y_1)/b = (z - z_1)/c`

We get given line passes through the point (x1 , x2 , x3 )

i.e., (5, - 4, 6) and direction ratios are (a, b, c)

i.e., (3, 7, –2).

Now, we can write vector equation of the line as `vecr = (5hati - 4hatj + 6hatk) + lambda(3hati + 7hatj - 2hatk)`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Introduction to Three Dimensional Geometry - Exercise [पृष्ठ २३९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 12 Introduction to Three Dimensional Geometry
Exercise | Q 47 | पृष्ठ २३९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Name the octants in which the following points lie:

(1, 2, 3), (4, –2, 3), (4, –2, –5), (4, 2, –5), (–4, 2, –5), (–4, 2, 5),

(–3, –1, 6), (2, –4, –7).


Name the octants in which the following points lie: (5, 2, 3)


Name the octants in which the following points lie:

(–5, 4, 3) 


Name the octants in which the following points lie: 

(4, –3, 5)


Name the octants in which the following points lie: 

(–5, –4, 7) 


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Planes are drawn parallel to the coordinate planes through the points (3, 0, –1) and (–2, 5, 4). Find the lengths of the edges of the parallelepiped so formed.


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Write the distance of the point P (2, 3,5) from the xy-plane.


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