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The angle between the planes r→.(2i^-3j^+k^) = 1 and r→.(i^-j^) = 4 is cos-1(-558).

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Question

The angle between the planes `vecr.(2hati - 3hatj + hatk)` = 1 and `vecr.(hati - hatj)` = 4 is `cos^-1((-5)/sqrt(58))`.

Options

  • True

  • False

MCQ
True or False
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Solution

This statement is True.

Explanation:

`vecb_1 = 2hati - 3hatj + hatk, vecb_2 = hati - hatj`

`cos theta = (|vecb_1 * vecb_2|)/(|vecb_1|*|vecb_2|)`

`cos theta = (|(2hati - 3hatj + hatk)*(hati - hatj)|)/(|2hati - 3hatj + hatk|*|hati - hatj|)`

= `(2 xx 1 - 3(-1) + (0))/(sqrt(4 + 9 + 1) * sqrt(1 + 1))`

= `(|2 + 3 + 0|)/(sqrt(4)*sqrt(2))`

= `5/sqrt(28)`.

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Chapter 12: Introduction to Three Dimensional Geometry - Exercise [Page 239]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 12 Introduction to Three Dimensional Geometry
Exercise | Q 45 | Page 239

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