English

Find the Image Of: (–2, 3, 4) in The Yz-plane. - Mathematics

Advertisements
Advertisements

Question

Find the image  of: 

 (–2, 3, 4) in the yz-plane.

Advertisements

Solution

(2,3,4)

shaalaa.com
  Is there an error in this question or solution?
Chapter 28: Introduction to three dimensional coordinate geometry - Exercise 15.1 [Page 6]

APPEARS IN

RD Sharma Mathematics [English] Class 11
Chapter 28 Introduction to three dimensional coordinate geometry
Exercise 15.1 | Q 2.1 | Page 6

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Coordinate planes divide the space into ______ octants.


If the origin is the centroid of the triangle PQR with vertices P (2a, 2, 6), Q (–4, 3b, –10) and R (8, 14, 2c), then find the values of a, b and c.


Name the octants in which the following points lie: 

(4, –3, 5)


Name the octants in which the following points lie: 

(–7, 2 – 5)


Find the image  of: 

 (–5, 0, 3) in the xz-plane. 


Find the image  of: 

 (–4, 0, 0) in the xy-plane. 


Determine the point on z-axis which is equidistant from the points (1, 5, 7) and (5, 1, –4).


Find the points on z-axis which are at a distance \[\sqrt{21}\]from the point (1, 2, 3). 


Show that the points A(3, 3, 3), B(0, 6, 3), C(1, 7, 7) and D(4, 4, 7) are the vertices of a square.


Find the locus of P if PA2 + PB2 = 2k2, where A and B are the points (3, 4, 5) and (–1, 3, –7).


Verify the following: 

 (0, 7, –10), (1, 6, –6) and (4, 9, –6) are vertices of an isosceles triangle.


Verify the following: 

 (–1, 2, 1), (1, –2, 5), (4, –7, 8) and (2, –3, 4) are vertices of a parallelogram.


Write the length of the perpendicular drawn from the point P(3, 5, 12) on x-axis.


The ratio in which the line joining (2, 4, 5) and (3, 5, –9) is divided by the yz-plane is


XOZ-plane divides the join of (2, 3, 1) and (6, 7, 1) in the ratio


The length of the perpendicular drawn from the point P (3, 4, 5) on y-axis is 


The perpendicular distance of the point P(3, 3,4) from the x-axis is 


The length of the perpendicular drawn from the point P(a, b, c) from z-axis is 


Find the coordinates of the point where the line through (3, – 4, – 5) and (2, –3, 1) crosses the plane passing through three points (2, 2, 1), (3, 0, 1) and (4, –1, 0)


A plane meets the co-ordinates axis in A, B, C such that the centroid of the ∆ABC is the point (α, β, γ). Show that the equation of the plane is `x/alpha + y/beta + z/γ` = 3


If a line makes an angle of `pi/4` with each of y and z axis, then the angle which it makes with x-axis is ______.


Prove that the lines x = py + q, z = ry + s and x = p′y + q′, z = r′y + s′ are perpendicular if pp′ + rr′ + 1 = 0.


Find the equation of a plane which bisects perpendicularly the line joining the points A(2, 3, 4) and B(4, 5, 8) at right angles.


If the line drawn from the point (–2, – 1, – 3) meets a plane at right angle at the point (1, – 3, 3), find the equation of the plane


Find the length and the foot of perpendicular from the point `(1, 3/2, 2)` to the plane 2x – 2y + 4z + 5 = 0.


Find the equation of the plane which is perpendicular to the plane 5x + 3y + 6z + 8 = 0 and which contains the line of intersection of the planes x + 2y + 3z – 4 = 0 and 2x + y – z + 5 = 0.


Show that the points `(hati - hatj + 3hatk)` and `3(hati + hatj + hatk)` are equidistant from the plane `vecr * (5hati + 2hatj - 7hatk) + 9` = 0 and lies on opposite side of it.


If l1, m1, n1 ; l2, m2, n2 ; l3, m3, n3 are the direction cosines of three mutually perpendicular lines, prove that the line whose direction cosines are proportional to l1 + l2 + l3, m1 + m2 + m3, n1 + n2 + n3 makes equal angles with them.


If the directions cosines of a line are k, k, k, then ______.


The locus represented by xy + yz = 0 is ______.


The direction cosines of the vector `(2hati + 2hatj - hatk)` are ______.


The vector equation of the line through the points (3, 4, –7) and (1, –1, 6) is ______.


The cartesian equation of the plane `vecr * (hati + hatj - hatk)` is ______.


The angle between the line `vecr = (5hati - hatj - 4hatk) + lambda(2hati - hatj + hatk)` and the plane `vec.(3hati - 4hatj - hatk)` + 5 = 0 is `sin^-1(5/(2sqrt(91)))`.


The line `vecr = 2hati - 3hatj - hatk + lambda(hati - hatj + 2hatk)` lies in the plane `vecr.(3hati + hatj - hatk) + 2` = 0.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×