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The unit vector normal to the plane x + 2y +3z – 6 = 0 is 114i^+214j^+314k^. - Mathematics

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प्रश्न

The unit vector normal to the plane x + 2y +3z – 6 = 0 is `1/sqrt(14)hati + 2/sqrt(14)hatj + 3/sqrt(14)hatk`.

विकल्प

  • True

  • False

MCQ
सत्य या असत्य
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उत्तर

This statement is True.

Explanation:

We have, `vecn = hati + 2hatj + 3hatk`

∴ `hatn = (hati + 2hatj + 3hatk)/sqrt(1^2 + 2^2 + 3^2)`

= `hati/sqrt(14) + (2hatj)/sqrt(14) + (3hatk)/sqrt(14)`

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अध्याय 12: Introduction to Three Dimensional Geometry - Exercise [पृष्ठ २३९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 12 Introduction to Three Dimensional Geometry
Exercise | Q 42 | पृष्ठ २३९

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