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Without Using the Derivative Show that the Function F (X) = 7x − 3 is Strictly Increasing Function on R ?

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Question

Without using the derivative show that the function f (x) = 7x − 3 is strictly increasing function on R ?

Sum
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Solution

\[\text { Here }, \]

\[f\left( x \right) = 7x - 3\]

\[\text { Let } x_1 , x_2 \text { in R such that } x_1 < x_2 . \text { Then },\]

\[ x_1 < x_2 \]

\[ \Rightarrow 7 x_1 < 7 x_2 \left[ \because 7 >0 \right]\]

\[ \Rightarrow 7 x_1 - 3 < 7 x_2 - 3\]

\[ \Rightarrow f\left( x_1 \right) < f\left( x_2 \right)\]

\[\therefore x_1 < x_2 \Rightarrow f\left( x_1 \right) < f\left( x_2 \right), \forall x_1 , x_2 \in R\]

\[\text { So,}f\left( x \right)\text {  is strictly increasing on R } .\]

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Chapter 16: Increasing and Decreasing Functions - Exercise 17.1 [Page 10]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 16 Increasing and Decreasing Functions
Exercise 17.1 | Q 9 | Page 10

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