Question

For \[f'(x)=12(x-3)(x+2)\], what are the critical points obtained from \[f'(x)=0\]?

Options

• \[x=-2,3\]

• \[x=-2,-3\]

• \[x=-3,2\]

• \[x=2,3\]

Answer 1

The derivative is zero when either factor is zero. Thus \[x-3=0\] gives \[x=3\], and \[x+2=0\] gives \[x=-2\].