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Karnataka Board PUCPUC Science Class 11

What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?

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Question

What will be the molarity of a solution, which contains 5.85 g of NaCl(s) per 500 mL?

Options

  • 4 mol L–1 

  • 20 mol L–1 

  • 0.2 mol L–1 

  • 2 mol L–1 

MCQ
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Solution

0.2 mol L–1 

Explanation:

No. of mole = `"Given mass"/"Molar mass"`

On substituting the value in the above equation, the cal, can be calculated as no, of mole = `(5.85  "g")/(58.5  "g mol"^-1)` = 0.1 g

The molarity (M) is given by the formula:

M = `n/V_((L))`

On substituting the values in the above equation:

Molarity = `(0.1  "mol" xx 1000  L)/500` = 0.2 mol L–1 

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Chapter 1: Some Basic Concepts of Chemistry - Multiple Choice Questions (Type - I) [Page 1]

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NCERT Exemplar Chemistry Exemplar [English] Class 11
Chapter 1 Some Basic Concepts of Chemistry
Multiple Choice Questions (Type - I) | Q 3 | Page 1

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