Advertisements
Advertisements
Question
Match the following physical quantities with units
| Physical quantity | Unit |
| (i) Molarity | (a) g mL–1 |
| (ii) Mole fraction | (b) mol |
| (iii) Mole | (c) Pascal |
| (iv) Molality | (d) Unitless |
| (v) Pressure | (e) mol L–1 |
| (vi) Luminous intensity | (f) Candela |
| (vii) Density | (g) mol kg–1 |
| (viii) Mass | (h) Nm–1 |
| (i) kg |
Advertisements
Solution
| Physical quantity | Unit |
| (i) Molarity | (e) mol L–1 |
| (ii) Mole fraction | (d) Unitless |
| (iii) Mole | (b) mol |
| (iv) Molality | (g) mol kg–1 |
| (v) Pressure | (c) Pascal |
| (vi) Luminous intensity | (f) Candela |
| (vii) Density | (a) g mL–1 |
| (viii) Mass | (i) kg |
Explanation:
(i) It is defined as the number of moles of solute dissolved in 1 litre of solution. So, the unit of molarity is mol L–1
(ii) Mole fraction is defined as the number of moles of a constituent divided by the total number of moles. So, it is unitless.
(iii) Mole is the unit to measure the amount of an atom or molecule in \[\ce{SI}\] system. it is symbolized as "mol".
(iv) It is defined as the number of moles of solute dissolved in 1 kg of solvent. so, the unit of morality is mol kg–1.
(v) It is defined as the force per unit area. so, the unit of pressure is Pascal.
(vi) It is the amount of visible light released per unit solid angle in unit time. so, it's unit will ve candela.
(vii) It is defined as the mass of a substance (in kg) divided by the volume of that substance (in mL). The unit of density is g mL–1.
(viii) Mass is used to measure the amount of a substance or an object. The unit of mass is kg.
APPEARS IN
RELATED QUESTIONS
If the density of methanol is 0.793 kg L–1, what is its volume needed for making 2.5 L of its 0.25 M solution?
Explain the term mole fraction.
Solve the following problem:
Find out the molar mass of the following compounds:
Mohr’s salt [FeSO4(NH4)2SO4.6H2O]
(At. mass: Cu = 63.5; S = 32; O = 16; H = 1; Na = 23; C = 12; Fe = 56; N = 14)
Solve the following problem:
Write the following number in ordinary decimal form:
3.49 × 10−11
Solve the following problem:
Write the following number in ordinary decimal form:
5.16 × 104
Solve the following problem:
Write the following number in ordinary decimal form:
0.011 × 10−3
Perform the following calculation. Round off your answer to three digits.
(8.39 107) (4.53 109)
Solve the following problem:
What weight of calcium oxide will be formed on heating 19.3 g of calcium carbonate?
(At. wt.: Ca = 40; C = 12; O = 16)
Solve the following problem:
The hourly energy requirements of an astronaut can be satisfied by the energy released when 34 grams of sucrose are “burnt” in his body. How many grams of oxygen would be needed to be carried in space capsule to meet his requirement for one day?
What are the favourable qualities given to gold when it is alloyed with copper or silver for the purpose of making ornaments?
Non-metals are usually poor conductors of heat and electricity. They are non-lustrous, non-sonorous, non-malleable and are coloured.
Name a lustrous non-metal.
A child wanted to separate the mixture of dyes constituting a sample of ink. He marked a line by the ink on the filter paper and placed the filter paper in a glass containing water as shown in Fig.2.3. The filter paper was removed when the water moved near the top of the filter paper.
(i) What would you expect to see, if the ink contains three different coloured components?
(ii) Name the technique used by the child.
(iii) Suggest one more application of this technique.
If the concentration of glucose \[\ce{(C6H12O6)}\] in blood is 0.9 g L–1, what will be the molarity of glucose in blood?
Sulphuric acid reacts with sodium hydroxide as follows:
\[\ce{H2SO4 + 2NaOH -> Na2SO4 + 2H2O}\]
When 1 L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained is:
(i) 0.1 mol L–1
(ii) 7.10 g
(iii) 0.025 mol L–1
(iv) 3.55 g
Which of the following solutions have the same concentration?
(i) \[\ce{20 g of NaOH in 200 mL of solution}\]
(ii) \[\ce{0.5 mol of KCl in 200 mL of solution}\]
(iii) \[\ce{40 g of NaOH in 100 mL of solution}\]
(iv) \[\ce{20 g of KOH in 200 mL of solution}\]
With increase of temperature, which of these changes?
Molarity of liquid HCl will be if the density of the solution is 1.17 g/cc.
Find the molality of solution if boiling point increases by 1.75 K and molal elevation constant of solvent is 5K kg mol-1.
