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Question
If the concentration of glucose \[\ce{(C6H12O6)}\] in blood is 0.9 g L–1, what will be the molarity of glucose in blood?
Options
5 M
50 M
0.005 M
0.5 M
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Solution
0.005 M
Explanation:
Molar mass of glucose \[\ce{(C6H12O6)}\]
= 12 × 6 + 1 × 12 + 16 × 6 = 180
Molarity = `("conc. in gL"^-1)/"Molar mass" = (0.90 "gL"^-1)/(180 "g mol"^-1)` = 0.005 M
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