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Karnataka Board PUCPUC Science Class 11

What will be the molality of the solution containing 18.25 g of HCl gas in 500 g of water?

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Question

What will be the molality of the solution containing 18.25 g of \[\ce{HCl}\] gas in 500 g of water?

Options

  • 0.1 m

  • 1 M

  • 0.5 m

  • 1 m

MCQ
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Solution

1 m

Explanation:

The number of moles is given by the following formula,

Moles = `"Mass"/"Molar mass"`  ......(1)

The number of moles of \[\ce{HCl}\] is calculated by using equation (1) as follows,

Moles of HCl = `(18.25 g)/((36.5 g)/(mol)` = 0.5 mol

The morality (m) is given by the formula:

m = `"n"/"mass of solvent"_((kg))`

On substituting the values in the above equation:

Molality = `(0.5  mol xx 1000  kg)/500` = 1 m

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Chapter 1: Some Basic Concepts of Chemistry - Multiple Choice Questions (Type - I) [Page 2]

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NCERT Exemplar Chemistry Exemplar [English] Class 11
Chapter 1 Some Basic Concepts of Chemistry
Multiple Choice Questions (Type - I) | Q 7 | Page 2

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