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Two soap bubbles have a radius in the ratio of 2:3. Compare the works done in blowing these bubbles.

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Question

Two soap bubbles have a radius in the ratio of 2:3. Compare the works done in blowing these bubbles.  

Sum
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Solution

Given: r1 : r2 = 2 : 3

To find: W1 : W2

Formula: W = 2TdA

Calculation: From the formula,

Work done to blow both bubbles,

W1 = `2T(4pir_1^2)` and W2 = `2T(4pir_2^2)`

∴ `"W"_1/"W"_2 = (r_1/r_2)^2 = (2/3)^2`

∴ W1 : W2 = 4 : 9

The ratio of work done to blow the bubbles is 4:9. 

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Chapter 2: Mechanical Properties of fluids - Short Answer I

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SCERT Maharashtra Physics [English] Standard 12 Maharashtra State Board
Chapter 2 Mechanical Properties of fluids
Short Answer I | Q 6

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