Advertisements
Advertisements
Question
Three resistors of 6.0 Ω, 2.0 Ω and 4.0 Ω are joined to an ammeter A and a cell of emf 6.0 V as shown in the following figure. Calculate :
- the effective resistance of the circuit.
- the reading of ammeter.
Advertisements
Solution
From circuit diagram
R3 and R2 are in series
R3 = i.e 4 + 2 = 6 Ω
Now R3 and R1 are in parallel
- Total resistance = `1/"R" = 1/6 + 1/6`
= `2/6` or
R = `6/2 `
= 3 Ω - I = `"V"/"R"`
= `6.0/3.0`
= 2 A
APPEARS IN
RELATED QUESTIONS
If the equivalent resistance is to be increased, then the number of resistances should be connected in
- Series
- Parallel
- Mixed arrangement
- None of the above
Write any two characteristics of a series combination of resistors.
The V-I graph for a series combination and for a parallel combination of two resistors is shown in the figure below. Which of the two A or B. represents the parallel combination? Give reasons for your answer.
What potential difference is needed to drive a current o f 1 A through a 5 Ω resistor?
When do you say that the resistors are connected in this way? Draw a circuit diagram.
A given metallic wire of resistance R is doubled on itself. What will be its new resistance?
Write an expression for calculating electrical power in terms of current and resistance.
State a relation between electrical power, resistance and potential difference in an electrical circuit.
Four resistances of 2.0Ω each are joined end to end, to form a square ABCD. Calculate the equivalent resistance of the combination between any two adjacent comers.
Two electric bulbs have resistances in the ratio 1 : 2. If they are joined in series, the energy consumed in them is in the ratio:
