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Karnataka Board PUCPUC Science 2nd PUC Class 12

Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. Determine the charge on each capacitor if the combination is connected to a 100 V supply.

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Question

Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. Determine the charge on each capacitor if the combination is connected to a 100 V supply.

Numerical
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Solution

Given: Supply voltage, V = 100 V

In a parallel combination, the potential difference across each capacitor is the same.

V1 = V2 = V3 = 100 V

Charge on a capacitor of capacitance C and potential difference V is given by the relation,

q = CV

For C1 = 2 pF,

q1 = C1V1

= 2 × 100

= 200 pC

= 2 × 10−10 C

For C2 = 3 pF,

q2 = C2V2

= 3 × 100

= 300 pC

= 3 × 10−10 C

For C3 = 4 pF,

q3 = C3V3

= 4 × 100

= 400 pC

= 4 × 10−10 C

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Chapter 2: Electrostatic Potential and Capacitance - EXERCISES [Page 79]

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NCERT Physics Part I and II [English] Class 12
Chapter 2 Electrostatic Potential and Capacitance
EXERCISES | Q 2.7 (b) | Page 79
NCERT Physics Part I and II [English] Class 12
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 2.7 (b) | Page 86

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