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Karnataka Board PUCPUC Science 2nd PUC Class 12

In the circuit shown in figure, initially K1 is closed and K2 is open. What are the charges on each capacitors. Then K1 was opened and K2 was closed (order is important),

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Question

In the circuit shown in figure, initially K1 is closed and K2 is open. What are the charges on each capacitors.

Then K1 was opened and K2 was closed (order is important), What will be the charge on each capacitor now? [C = 1µF]

Long Answer
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Solution


Initially: `V oo 1/C` and `V_1 + V_2 = E`

⇒ `V_1 = 3V` and `V_2 = 6V`

∴ `Q_1 = C_1V_1 = 6C xx 3 = 18muC`

`Q_2 = 9muC` and `Q_3 = 0`

Later: `Q_2 = Q"'"_2 + Q_3`

With `C_2V + C_3V = Q2`

⇒ `V = Q_2/(C_2 + C_3) = (3/2)V`

`Q"'"_2 = (9/2)muC` and  `Q"'"_3 = (9/2)muC`

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Chapter 2: Electrostatic Potential And Capacitance - MCQ I [Page 15]

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NCERT Exemplar Physics Exemplar [English] Class 12
Chapter 2 Electrostatic Potential And Capacitance
MCQ I | Q 2.3 | Page 15

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